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Let T be the statement: For all real numbers x and y with x < y, there exists an integer n such that x ≤ n ≤ y.Write the negation of T.

Question

Let T be the statement:

For all real numbers x and y with x < y, there exists an integer n such that x ≤ n ≤ y.

Write the negation of T.

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Solution

To negate the statement T, we will follow the logical steps necessary to express the opposite of the original statement.

1. ### Identify the Original Statement

The original statement T is: "For all real numbers x x and y y with x<y x < y , there exists an integer n n such that xny x \leq n \leq y ."

2. ### Break Down the Statement

  • The phrase "For all real numbers x x and y y with x<y x < y " is a universal quantifier, which we will negate to an existential quantifier.
  • The phrase "there exists an integer n n such that xny x \leq n \leq y " is an existential quantifier that we will negate to a universal quantifier.

3. ### Formulate the Negation

The negation can be constructed as follows:

  • The phrase "For all x x and y y with x<y x < y " becomes "There exist x x and y y such that x<y x < y ."
  • The phrase "there exists an integer n n " becomes "for all integers n n ."

Thus, the negated statement ¬T \neg T is reformulated as: "There exist real numbers x x and y y such that x<y x < y and for all integers n n , it is not true that xny x \leq n \leq y ."

4. ### Final Statement of the Negation

Putting it all together, the negation of statement T is: "There exist real numbers x x and y y such that x<y x < y and for all integers n n , n<x n < x or n>y n > y ."

This means that no integer n n can be found between x x and y y , which effectively states that there is no integer within that interval.

This problem has been solved

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