What is wrong with the following code?int n = 0;int array[5];int i = 3;array[n] = i;

1. Break Down the Problem

The code provided declares an integer variable n, an integer array array of size 5, and an integer variable i. It then assigns the value of i to the array at the index specified by n.

2. Relevant Concepts

In C/C++ programming, array indexing starts from 0. This means that for an array declared as array[5], valid indices are 0, 1, 2, 3, and 4. Assigning to an invalid index could lead to undefined behavior.

3. Analysis and Detail

• The variable n is initialized to 0.
• The array array can hold 5 elements at indices 0 to 4.
• The line array[n] = i; assigns the value of i (which is 3) to array[0]. This is a valid operation since 0 is within the bounds of the array.

The code itself does not contain any syntax errors or out-of-bounds issues. However, if there are subsequent operations trying to access array[n] or other indices without proper checks, it can lead to issues.

4. Verify and Summarize

• There are no apparent errors in the code snippet as given.
• The assignment array[n] = i; is valid and will execute correctly.
• The code initializes values, but if more operations are added (for example, incrementing n), those would need checks for valid index access to avoid potential issues.

Final Answer

The code appears valid based on the snippet provided, and there are no errors in the assignment. However, always ensure that n stays within the bounds of array to prevent undefined behavior in more complex operations.