An excitatory local potential will make the neuron Blank______ likely to generate a nerve impulse.Multiple choice question.moreless

The correct answer is "more" likely to generate a nerve impulse.

Explanation

An excitatory local potential, often caused by neurotransmitters binding to receptors on a neuron's membrane, causes depolarization of that membrane. This means that the internal environment of the neuron becomes less negative (or more positive) relative to the outside. When the excitatory potential is strong enough to reach a certain threshold, it triggers an action potential, or nerve impulse.

In summary, the local potential increases the likelihood of the neuron reaching the threshold necessary for firing an action potential. Unlike inhibitory potentials, which decrease this likelihood, excitatory potentials push the membrane potential toward the critical point where a nerve impulse can occur. Thus, the neuron becomes more likely to generate a nerve impulse in response to excitatory local potentials.