The sound of a band is rated as 60 dB at a distance of 10.0 m. What is the sound intensity level of the band when one is 20.0 m from the band?

The sound intensity level (in dB) decreases by 6 dB each time the distance is doubled. This is known as the inverse square law.

Here's how you can calculate it:

1. Identify the initial sound intensity level and distance. In this case, it's 60 dB at 10.0 m.
2. Determine the new distance. In this case, it's 20.0 m, which is twice the initial distance.
3. Apply the inverse square law. Since the distance doubled, the sound intensity level will decrease by 6 dB.
4. Subtract 6 dB from the initial sound intensity level.

So, 60 dB - 6 dB = 54 dB.

Therefore, the sound intensity level of the band when one is 20.0 m from the band is 54 dB.