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If 36, p 9 andą are consecutive terms of an exponential sequence (GP). Find the sum of p and q.

Question

If 36, p, 9 and q are consecutive terms of an exponential sequence (GP). Find the sum of p and q.

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Solution

In an exponential sequence (also known as a geometric progression), each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio.

Given that 36, p, 9, and q are consecutive terms of an exponential sequence, we can set up the following equations based on the property of geometric progression:

  1. p/36 = 9/p (because the ratio between consecutive terms is constant)
  2. 9/p = q/9

From equation 1), we can solve for p: p^2 = 36 * 9 p = sqrt(36 * 9) p = 18

Substitute p = 18 into equation 2) to solve for q: 9/18 = q/9 q = 9 * 9 / 18 q = 4.5

Finally, the sum of p and q is 18 + 4.5 = 22.5.

This problem has been solved

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