An HDD has an average seek time of 3ms, a rotation time of 4ms, and a transfer time of 0.01s. What is the average I/O time?
Question
An HDD has an average seek time of 3ms, a rotation time of 4ms, and a transfer time of 0.01s. What is the average I/O time?
Solution
The average I/O time for a hard disk drive (HDD) can be calculated by adding the average seek time, rotation time, and transfer time.
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Convert all times to the same unit. In this case, we'll use milliseconds (ms). The transfer time is given in seconds, so we need to convert it to milliseconds. 1 second is equal to 1000 milliseconds, so 0.01 seconds is equal to 10 milliseconds.
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Add the times together:
- Average seek time = 3ms
- Rotation time = 4ms
- Transfer time = 10ms
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Average I/O time = Average seek time + Rotation time + Transfer time = 3ms + 4ms + 10ms = 17ms
So, the average I/O time of the HDD is 17ms.
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