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Suppose n is a number such that the mean (average) of the list of numbers 2, 9, 4, n, 2nis equal to 6. What is the value of n?

Question

Suppose n is a number such that the mean (average) of the list of numbers 2, 9, 4, n, 2n is equal to 6. What is the value of n?

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Solution

To find the value of n, we need to set up an equation based on the information given in the problem.

The mean (average) of a list of numbers is calculated by adding up all the numbers in the list and then dividing by the number of items in the list.

In this case, the list of numbers is 2, 9, 4, n, and 2n, and we know that the mean of these numbers is 6.

So, we can set up the following equation:

(2 + 9 + 4 + n + 2n) / 5 = 6

Solving this equation will give us the value of n.

First, simplify the numerator:

15 + 3n = 6 * 5

15 + 3n = 30

Then, subtract 15 from both sides of the equation:

3n = 15

Finally, divide both sides by 3 to solve for n:

n = 5

So, the value of n that makes the mean of the list 6 is 5.

This problem has been solved

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