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All the following sequences converge to 1 except ..........*1 pointv_n={ n/(2n+1) }u_n={ 2n/(2n+1) }w_n={ (1+n)/(7+n) }z_n={ (n+3)/(n+4) }

Question

All the following sequences converge to 1 except ..........*1 point

v_n={ n/(2n+1) }
u_n={ 2n/(2n+1) }
w_n={ (1+n)/(7+n) }
z_n={ (n+3)/(n+4) }

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Solution

To determine which sequence does not converge to 1, we need to find the limit of each sequence as n approaches infinity.

  1. For v_n={ n/(2n+1) }, as n approaches infinity, the sequence becomes n/n which is 1. So, v_n converges to 1.

  2. For u_n={ 2n/(2n+1) }, as n approaches infinity, the sequence becomes 2n/2n which is also 1. So, u_n converges to 1.

  3. For w_n={ (1+n)/(7+n) }, as n approaches infinity, the sequence becomes n/n which is 1. So, w_n converges to 1.

  4. For z_n={ (n+3)/(n+4) }, as n approaches infinity, the sequence becomes n/n which is 1.

However, the sequence z_n={ (n+3)/(n+4) } does not converge to 1. As n approaches infinity, the sequence becomes (n/n) + (3/n) / (n/n) + (4/n), which simplifies to 1 + (3/n) / 1 + (4/n). As n approaches infinity, (3/n) and (4/n) both approach 0, so the sequence converges to 1 + 0 / 1 + 0 = 1.

So, all the sequences converge to 1. There seems to be a mistake in the question as all the given sequences converge to 1.

This problem has been solved

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