The output of the JavaScript code will be `5`.

Here's the step-by-step explanation:

1. The code defines an immediately invoked function expression (IIFE) that sets `a` and `b` to `5`.

2. The `var` keyword only applies to `a`, making `a` a local variable within the function.

3. `b` is not declared with `var`, so it is set as a global variable.

4. After the function is executed, `a` is discarded because it's local to the function, but `b` remains because it's global.

5. When `console.log(b)` is called outside of the function, it logs the global variable `b`, which is `5`.

Question

The output of the JavaScript code will be `5`.

Here's the step-by-step explanation:

1. The code defines an immediately invoked function expression (IIFE) that sets `a` and `b` to `5`.

2. The `var` keyword only applies to `a`, making `a` a local variable within the function.

3. `b` is not declared with `var`, so it is set as a global variable.

4. After the function is executed, `a` is discarded because it's local to the function, but `b` remains because it's global.

5. When `console.log(b)` is called outside of the function, it logs the global variable `b`, which is `5`.

Knowee AI · Accepted Answer

The output of the JavaScript code will be `5`.

Here's the step-by-step explanation:

1. The code defines an immediately invoked function expression (IIFE) that sets `a` and `b` to `5`.

2. The `var` keyword only applies to `a`, making `a` a local variable within the function.

3. `b` is not declared with `var`, so it is set as a global variable.

4. After the function is executed, `a` is discarded because it's local to the function, but `b` remains because it's global.

5. When `console.log(b)` is called outside of the function, it logs the global variable `b`, which is `5`.

What will the following JavaScript code output?(function() { var a = b = 5;})();console.log(b);5ReferenceError: b is not definednullundefined