Ang Habaaa! If the frequency of oscillation of the EM wave in vacuum is 1.5×1015 [Hz], what isits wavelength?A. 50 [nm]B. 100 [nm]C. 200 [nm]D. 400 [nm]

Question

Ang Hababaa!

If the frequency of oscillation of the EM wave in vacuum is $1.5 \times 10^{15} \text{ [Hz]}$ , what is its wavelength?
A. 50 [nm]
B. 100 [nm]
C. 200 [nm]
D. 400 [nm]

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Solution

The speed of light (c) in a vacuum is a constant, approximately 3.00 x 10^8 meters per second. The frequency (f) of the wave is given as 1.5 x 10^15 Hz. The wavelength (λ) can be found using the formula for the speed of light: c = λf.

Rearranging the formula to solve for the wavelength gives: λ = c / f.

Substituting the given values into the formula gives: λ = (3.00 x 10^8 m/s) / (1.5 x 10^15 Hz) = 0.2 x 10^-6 meters.

To convert meters to nanometers, multiply by 1 x 10^9: 0.2 x 10^-6 m * 1 x 10^9 nm/m = 200 nm.

So, the wavelength of the EM wave is 200 nm, which corresponds to option C.

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Ang Habaaa! If the frequency of oscillation of the EM wave in vacuum is 1.5×1015 [Hz], what isits wavelength?A. 50 [nm]B. 100 [nm]C. 200 [nm]D. 400 [nm]

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Ang Hababaa!

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