It takes 60 N to pull a 5.0 kg object with a “non-slip” matt at a constant speed on a table.What is the coefficient of kinetic friction?
Question
It takes 60 N to pull a 5.0 kg object with a “non-slip” matt at a constant speed on a table. What is the coefficient of kinetic friction?
Solution
To find the coefficient of kinetic friction, we first need to find the force of friction. Since the object is moving at a constant speed, the force of friction is equal to the applied force, which is 60 N.
Next, we need to find the normal force. This is the force exerted by a surface that supports the weight of an object resting on it. It acts perpendicular to the surface. For an object resting on a horizontal surface with no vertical forces acting on it other than gravity, the normal force is equal to the weight of the object. The weight of the object is its mass times the acceleration due to gravity.
So, the normal force (N) = mass (m) * gravity (g) N = 5.0 kg * 9.8 m/s² = 49 N
The coefficient of kinetic friction (μk) is then calculated by dividing the force of friction (Ff) by the normal force (N).
So, μk = Ff / N μk = 60 N / 49 N = 1.22
Therefore, the coefficient of kinetic friction is 1.22.
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