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Suppose X∼N(16.5,2) , and x=18.5 . Find and interpret the z -score of the standardized normal random variable.

Question

Suppose

X∼N(16.5,2) , and x=18.5 .
Find and interpret the z -score of the standardized normal random variable.

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Solution

The z-score is a measure of how many standard deviations an element is from the mean. To calculate the z-score, we use the formula:

z = (x - μ) / σ

where:

  • x is the element
  • μ is the mean
  • σ is the standard deviation

In this case, we have:

  • x = 18.5
  • μ = 16.5
  • σ = 2

Substituting these values into the formula, we get:

z = (18.5 - 16.5) / 2 = 1

So, the z-score of the standardized normal random variable is 1. This means that the value 18.5 is one standard deviation above the mean.

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