The atomic radius generally increases as we move down a group in the periodic table because additional electron shells are added. Also, anions (negative ions) are larger than their parent atoms because the addition of electrons increases electron-electron repulsion, causing the electron cloud to expand.

1. Cl: Chlorine is in the 3rd period of the periodic table, so it has three electron shells.

2. Br: Bromine is in the 4th period, so it has four electron shells, making it larger than chlorine.

3. I: Iodine is in the 5th period, so it has five electron shells, making it larger than bromine.

4. I-: Iodine ion is larger than the iodine atom because the addition of an electron increases electron-electron repulsion, causing the electron cloud to expand.

So, the order from smallest to largest atomic radius is: Cl

Question

The atomic radius generally increases as we move down a group in the periodic table because additional electron shells are added. Also, anions (negative ions) are larger than their parent atoms because the addition of electrons increases electron-electron repulsion, causing the electron cloud to expand.

1. Cl: Chlorine is in the 3rd period of the periodic table, so it has three electron shells.

2. Br: Bromine is in the 4th period, so it has four electron shells, making it larger than chlorine.

3. I: Iodine is in the 5th period, so it has five electron shells, making it larger than bromine.

4. I-: Iodine ion is larger than the iodine atom because the addition of an electron increases electron-electron repulsion, causing the electron cloud to expand.

So, the order from smallest to largest atomic radius is: Cl < Br < I < I-.

Knowee AI · Accepted Answer

The atomic radius generally increases as we move down a group in the periodic table because additional electron shells are added. Also, anions (negative ions) are larger than their parent atoms because the addition of electrons increases electron-electron repulsion, causing the electron cloud to expand.

1. Cl: Chlorine is in the 3rd period of the periodic table, so it has three electron shells.

2. Br: Bromine is in the 4th period, so it has four electron shells, making it larger than chlorine.

3. I: Iodine is in the 5th period, so it has five electron shells, making it larger than bromine.

4. I-: Iodine ion is larger than the iodine atom because the addition of an electron increases electron-electron repulsion, causing the electron cloud to expand.

So, the order from smallest to largest atomic radius is: Cl < Br < I < I-.

Rank the following atoms/ions in order of atomic radius from smallest to largest: Br / Cl / I- / I

Question

Rank the following atoms/ions in order of atomic radius from smallest to largest:

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