What will the result of num1 variable after execution of the following statements? int j = 1, num1 = 4; while (++j <= 10) { num1++; } ans.

To determine the result of the num1 variable after executing the provided statements, we can analyze the code step by step.

1. Break Down the Problem

• We start with two variables: j initialized to 1 and num1 initialized to 4.
• A while loop increments j and checks if it is less than or equal to 10.
• For each iteration of the loop, num1 is incremented by 1.

2. Relevant Concepts

• The loop condition is ++j <= 10, which means j is incremented first and then checked against 10.
• The loop will continue executing as long as j is less than or equal to 10.

3. Analysis and Detail

• Initially:

  • j = 1
  • num1 = 4

• Loop Iterations:

  • Iteration 1: j becomes 2, num1 becomes 5.
  • Iteration 2: j becomes 3, num1 becomes 6.
  • Iteration 3: j becomes 4, num1 becomes 7.
  • Iteration 4: j becomes 5, num1 becomes 8.
  • Iteration 5: j becomes 6, num1 becomes 9.
  • Iteration 6: j becomes 7, num1 becomes 10.
  • Iteration 7: j becomes 8, num1 becomes 11.
  • Iteration 8: j becomes 9, num1 becomes 12.
  • Iteration 9: j becomes 10, num1 becomes 13.
  • Iteration 10: j becomes 11, loop terminates (because 11 > 10).

4. Verify and Summarize

• The num1 variable started at 4 and was incremented a total of 9 times (from j = 2 to j = 10).
• Therefore, num1 becomes $4 + 9 = 13$.

Final Answer

The result of the num1 variable after the execution of the statements will be 13.