If the input in BPF (experiment 6) is 0.3V p-p sine wave, what is the maximum p-p final output we can expect?a.1.2V p-pb.0.9V p-pc.2.4V p-pd.0.6V p-p

1. Break Down the Problem

To determine the maximum peak-to-peak (p-p) output voltage from a band-pass filter (BPF) when given an input sine wave, we need to consider the gain of the filter. Assuming the filter behaves ideally, we will compare the input voltage and the provided options to deduce the output.

2. Relevant Concepts

The output voltage of a BPF can be calculated using the formula: $V_{\text{out(p-p)}} = V_{\text{in(p-p)}} \times G$ where $G$ is the gain of the filter. Gain is determined based on the specifications of the filter in the given experiment.

3. Analysis and Detail

Given:

• Input Voltage $V_{\text{in(p-p)}} = 0.3\,V$

Assuming maximum gain for a practical BPF typically ranges from 1 to 8 or 10, the output could be a multiple of the input.

For the options provided:

• For a gain of 1: $V_{\text{out(p-p)}} = 0.3V$
• For a gain of 2: $V_{\text{out(p-p)}} = 0.6V$
• For a gain of 3: $V_{\text{out(p-p)}} = 0.9V$
• For a gain of 4: $V_{\text{out(p-p)}} = 1.2V$
• For a gain of 8: $V_{\text{out(p-p)}} = 2.4V$

4. Verify and Summarize

The maximum output voltage we can expect varies based on the pre-defined characteristics of the filter. Given that the input initial condition is a 0.3V p-p signal, the multiple-choice answers show a range of possible outputs depending on gain.

Final Answer

Considering the options provided:

The maximum peak-to-peak output we can expect is likely 1.2V p-p (Option a) if the gain is set at approximately 4. If higher gain is achievable, 2.4V p-p could also be possible but that depends on filter specifications not provided explicitly in the problem.