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The circle below has center O, and its radius is 9m. Given that =m∠AOB40°, find the area of the shaded region and the length of the arc ADB.

Question

The circle below has center O, and its radius is 9m.

Given that mAOB=40° m∠AOB = 40° , find the area of the shaded region and the length of the arc ADB.

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Solution

1. Break Down the Problem

To find the area of the shaded region and the length of the arc ADB, we will:

  1. Calculate the area of sector AOB.
  2. Calculate the length of arc ADB.

2. Relevant Concepts

  • Area of a sector: A=θ360×πr2 A = \frac{\theta}{360^\circ} \times \pi r^2
  • Length of an arc: L=θ360×2πr L = \frac{\theta}{360^\circ} \times 2\pi r

Where:

  • θ \theta is the angle in degrees,
  • r r is the radius of the circle.

3. Analysis and Detail

Step 1: Calculate the area of sector AOB

Using the formula for the area of a sector:

A=40360×π×(9m)2 A = \frac{40^\circ}{360^\circ} \times \pi \times (9m)^2

Calculating this:

A=40360×π×81 A = \frac{40}{360} \times \pi \times 81

A=19×π×81 A = \frac{1}{9} \times \pi \times 81

A=9πm2 A = 9\pi \, \text{m}^2

Step 2: Calculate the length of arc ADB

Using the formula for the length of an arc:

L=40360×2π×9m L = \frac{40^\circ}{360^\circ} \times 2\pi \times 9m

Calculating this:

L=40360×2π×9 L = \frac{40}{360} \times 2\pi \times 9

L=19×2π×9 L = \frac{1}{9} \times 2\pi \times 9

L=2πm L = 2\pi \, \text{m}

4. Verify and Summarize

We calculated:

  • The area of the shaded region (sector AOB) is 9πm2 9\pi \, \text{m}^2 .
  • The length of the arc ADB is 2πm 2\pi \, \text{m} .

Final Answer

  • Area of the shaded region: 9πm2 9\pi \, \text{m}^2
  • Length of the arc ADB: 2πm 2\pi \, \text{m}

This problem has been solved

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