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Simplify the following expression.‐3 + 7(a – 3b – 1) – 4(10 – a + 2b)11a - 11b - 4411a - 29b - 503a - 13b - 506a - b - 44

Question

Simplify the following expression.

-3 + 7(a – 3b – 1) – 4(10 – a + 2b)

11a - 11b - 44

11a - 29b - 50

3a - 13b - 50

6a - b - 44

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Solution

1. Break Down the Problem

We need to simplify the given expression:
3+7(a3b1)4(10a+2b)-3 + 7(a - 3b - 1) - 4(10 - a + 2b) followed by 11a11b4411a - 11b - 44 and other similar expressions.

2. Relevant Concepts

We will apply the distributive property to expand the terms and then combine like terms. The distributive property states that a(b+c)=ab+aca(b + c) = ab + ac.

3. Analysis and Detail

Let's simplify the expression step-by-step:

  1. Expand the expressions:

    • First term: 7(a3b1)=7a21b7 7(a - 3b - 1) = 7a - 21b - 7
    • Second term: 4(10a+2b)=40+4a8b -4(10 - a + 2b) = -40 + 4a - 8b
  2. Combine the terms: 3+(7a21b7)+(40+4a8b) -3 + (7a - 21b - 7) + (-40 + 4a - 8b) Combining the constant terms and coefficients of aa and bb: (3740)+(7a+4a)+(21b8b) (-3 - 7 - 40) + (7a + 4a) + (-21b - 8b) which simplifies to: 50+11a29b -50 + 11a - 29b

  3. Add the remaining expressions: Combine our result with 11a11b4411a - 11b - 44: (50+11a29b)+(11a11b44) (-50 + 11a - 29b) + (11a - 11b - 44) Again, combine like terms: 11a+11a29b11b5044 11a + 11a - 29b - 11b - 50 - 44 This gives: 22a40b94 22a - 40b - 94

4. Verify and Summarize

We’ve correctly expanded and combined the terms according to algebraic rules. All calculations have been verified at each step.

Final Answer

The final simplified expression is:
22a40b94 22a - 40b - 94

This problem has been solved

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