Given a shear stress of txy = 35 000 kPa and a shear modulus of G = 75 GPa, the shear strain is most nearly

Question

Given a shear stress of $t_{xy} = 35,000 \ \text{kPa}$ and a shear modulus of $G = 75 \ \text{GPa}$ , the shear strain is most nearly

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Solution

The shear strain (γ) can be calculated using the formula:

γ = τ/G

where: τ is the shear stress, and G is the shear modulus.

Given that τ = 35,000 kPa = 35,000,000 Pa (since 1 kPa = 1000 Pa) and G = 75 GPa = 75,000,000,000 Pa (since 1 GPa = 1,000,000,000 Pa), we can substitute these values into the formula:

γ = 35,000,000 Pa / 75,000,000,000 Pa = 0.000467

Therefore, the shear strain is most nearly 0.000467.

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Given a shear stress of txy = 35 000 kPa and a shear modulus of G = 75 GPa, the shear strain is most nearly

Question

Given a shear stress of txy=35,000 kPa t_{xy} = 35,000 \ \text{kPa} txy​=35,000 kPa and a shear modulus of G=75 GPa G = 75 \ \text{GPa} G=75 GPa, the shear strain is most nearly

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Given a shear stress of $t_{xy} = 35,000 \ \text{kPa}$ and a shear modulus of $G = 75 \ \text{GPa}$ , the shear strain is most nearly