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What is the value of b in the solution of the system of equations below? 6a + 3b = 12-2a + b = -8

Question

What is the value of b in the solution of the system of equations below?

  1. 6a+3b=126a + 3b = 12
  2. 2a+b=8-2a + b = -8
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Solution

To find the value of b in the system of equations, we can use the method of substitution or elimination. Here, we will use the elimination method.

The system of equations is:

6a + 3b = 12 -2a + b = -8

First, we can multiply the second equation by 3 to make the coefficients of b in both equations the same:

-6a + 3b = -24

Now we have:

6a + 3b = 12 -6a + 3b = -24

We can add these two equations together:

(6a - 6a) + (3b + 3b) = 12 - 24 0a + 6b = -12

Simplify to get:

b = -12 / 6 b = -2

So, the value of b in the solution of the system of equations is -2.

This problem has been solved

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