If A is the set of all natural numbers whereas B is the set of negative of natural numbers then A ⋂ B is{0}{-1, 1}{...-2, -1, +1, +2, …}{}

To determine the intersection of sets $A$ and $B$, we need to analyze both sets:

1. Definition of Set A:

   • Set $A$ consists of all natural numbers, which can be represented as: $A = \{1, 2, 3, 4, \ldots\}$

2. Definition of Set B:

   • Set $B$ consists of all negative natural numbers, which can be represented as: $B = \{-1, -2, -3, -4, \ldots\}$

3. Finding the Intersection (A ∩ B):

   • The intersection of two sets includes only the elements that are present in both sets.
   • Since set $A$ contains only positive natural numbers and set $B$ contains only negative numbers, there are no common elements between the two sets.

4. Conclusion:

   • Therefore, the intersection of sets $A$ and $B$ can be denoted as: $A \cap B = \emptyset$
   • In other words, the intersection is an empty set.

Final Answer

The intersection $A \cap B$ is: $\emptyset$