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19.7 kg of gold was recovered from a smuggler. How many atoms of gold were recovered. (Molar mass of Au = 197)1006.023 × 10236.023 × 10246.023 × 1025

Question

19.7 kg of gold was recovered from a smuggler. How many atoms of gold were recovered.

(Molar mass of Au = 197)

  • 1006.023 × 10²
  • 36.023 × 10²
  • 46.023 × 10²
  • 5
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Solution

To find the number of atoms in 19.7 kg of gold, we first need to convert the mass from kilograms to grams because the molar mass of gold is given in grams per mole.

  1. Convert the mass from kg to g: 19.7 kg = 19,700 g

  2. Use the molar mass of gold to find the number of moles: Number of moles = mass / molar mass Number of moles = 19,700 g / 197 g/mol = 100 moles

  3. Use Avogadro's number to find the number of atoms: Number of atoms = number of moles * Avogadro's number Number of atoms = 100 moles * 6.023 x 10^23 atoms/mole = 6.023 x 10^25 atoms

So, the number of gold atoms recovered from the smuggler is 6.023 x 10^25.

This problem has been solved

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