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What will be the output of the following Python code?min = (lambda x, y: x if x < y else y) min(101*99, 102*98)

Question

What will be the output of the following Python code?

min = (lambda x, y: x if x &lt; y else y)
min(101*99, 102*98)
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Solution

The given Python code is incorrect. It seems like you're trying to use a lambda function to find the minimum of two numbers. However, the syntax is incorrect. Here's the correct code:

min = (lambda x, y: x if x < y else y)
print(min(101*99, 102*98))

The lambda function takes two arguments, x and y, and returns x if x is less than y, else it returns y. This is essentially a way to find the minimum of two numbers.

In the print statement, we're calling this lambda function with two arguments: 10199 and 10298. It will return the smaller of these two numbers.

10199 = 9999 10298 = 9996

So, the output of the correct Python code will be 9996.

This problem has been solved

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