the product of two consecutive negative even integers is 80. Find the value of the lesser integer.
Question
Solution 1
Let's denote the two consecutive negative even integers as x and x+2.
Since the product of these two integers is 80, we can write the equation as:
x * (x + 2) = 80
Expanding this equation gives:
x^2 + 2x = 80
Rearranging the terms to form a quadratic equation gives:
x^2 + 2x - 80 = 0
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