Consider the following atoms: 16O, 18O, 18F, and 18Ne. Which have the same number of neutrons? 18F and 16O 16O, 18F, and 18Ne 16O and 18Ne 16O and 18O
Question
Consider the following atoms: 16O, 18O, 18F, and 18Ne. Which have the same number of neutrons?
- 18F and 16O
- 16O, 18F, and 18Ne
- 16O and 18Ne
- 16O and 18O
Solution
To answer this question, we first need to understand the notation used for atoms. The number before the element symbol (O, F, Ne) is the atomic mass number, which is the sum of protons and neutrons in the nucleus. The atomic number (number of protons), which defines the element, is not given here but can be found on the periodic table.
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16O: Oxygen's atomic number is 8, so it has 8 protons. Subtracting the number of protons from the atomic mass number (16 - 8), we find that 16O has 8 neutrons.
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18O: Again, oxygen has 8 protons. So, 18O has 10 neutrons (18 - 8).
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18F: Fluorine's atomic number is 9, so it has 9 protons. Therefore, 18F has 9 neutrons (18 - 9).
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18Ne: Neon's atomic number is 10, so it has 10 protons. Therefore, 18Ne has 8 neutrons (18 - 10).
So, the atoms 16O and 18Ne have the same number of neutrons.
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