Find the gradient of the straight line passing through the points (2, 3) and (1, 6)
Question
Find the gradient of the straight line passing through the points (2, 3) and (1, 6)
Solution
To find the gradient of the straight line passing through the points (2, 3) and (1, 6), we can use the formula:
Gradient = (change in y) / (change in x)
First, let's calculate the change in y. The y-coordinate of the first point is 3, and the y-coordinate of the second point is 6. So, the change in y is 6 - 3 = 3.
Next, let's calculate the change in x. The x-coordinate of the first point is 2, and the x-coordinate of the second point is 1. So, the change in x is 1 - 2 = -1.
Now, we can substitute these values into the formula:
Gradient = (change in y) / (change in x) = 3 / -1 = -3
Therefore, the gradient of the straight line passing through the points (2, 3) and (1, 6) is -3.
Similar Questions
A straight line is drawn through the points with coordinates (–3, 26) and (5, 2).Calculate the gradient of the line.
A line passes through the points (–2,6) and (1,–9). Write its equation in slope-intercept form.
Write an equation in point-slope form for the line that passes through the given points.(4,−6), (6,−4)4,-6, 6,-4
Find the slope of the line passing through the points −−3, 8 and 4, 6. Undefined
What is the gradient of the straight line perpendicular to the straight line y = -3x + 4
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.