What is the % relative humidity at 25ºCand 0.01876 atm if the vapor pressure ofwater is 23.76 mm Hg.a. 40%b. 50%c. 60%d. 70%
Question
What is the % relative humidity at 25ºC and 0.01876 atm if the vapor pressure of water is 23.76 mm Hg.
- a. 40%
- b. 50%
- c. 60%
- d. 70%
Solution
To answer this question, we need to understand what relative humidity is. Relative humidity is the amount of moisture in the air compared to the maximum amount of moisture the air could hold at the same temperature. It is usually expressed as a percentage.
Here are the steps to calculate the relative humidity:
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Convert the given pressure from atm to mm Hg. 1 atm is approximately equal to 760 mm Hg. So, 0.01876 atm would be equal to 0.01876 * 760 = 14.2576 mm Hg.
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The vapor pressure of water at 25ºC is given as 23.76 mm Hg. This is the maximum amount of moisture the air could hold at this temperature.
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The actual amount of moisture in the air is given by the pressure of 14.2576 mm Hg.
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Now, we can calculate the relative humidity by dividing the actual amount of moisture by the maximum amount of moisture and then multiplying by 100 to get a percentage.
So, Relative Humidity = (14.2576 / 23.76) * 100 = 60%
Therefore, the relative humidity at 25ºC and 0.01876 atm is 60%, so the answer is c. 60%.
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