If x, y, z are positive integers, such that xy + x + y = 215, yz + y + z = 161 and zx + z + x = 107, then (y – z)/(x – z) =
Question
If x, y, z are positive integers, such that
then
Solution
1. Break Down the Problem
We have three equations involving positive integers , , and :
We need to find the value of .
2. Relevant Concepts
We can rearrange the equations to express them in a more manageable form:
- From , we can rearrange to .
- Similar rearrangements can be made for the other two equations.
Let's rewrite each equation:
3. Analysis and Detail
Now we will factor each equation based on the products obtained:
-
First Equation: The factors of 216 are:
-
Second Equation: The factors of 162 are:
-
Third Equation: The factors of 108 are:
We will find valid combinations from the factor pairs of each equation.
4. Verification through substitution
Let’s try combining factors that appear among the products:
Starting with the equation :
- Let and , then and .
Next, substituting into :
- If , then (not valid).
So we discard this pair and try another:
Set (then ) and (then ):
- Calculate for using :
Now we verify with the third equation:
- Check :
Final Answer
Now we can compute:
Thus, the final answer is:
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