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Twenty years hence Ron will be five times as he was 36 years ago, his present age is:  Ops:   A. 65 years    B. 40 years    C. 48 years    D. 50 years

Question

Twenty years hence Ron will be five times as he was 36 years ago, his present age is:

  • Ops:
    A. 65 years
    B. 40 years
    C. 48 years
    D. 50 years
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Solution

1. Break Down the Problem

Let Ron's present age be x x . According to the problem, we have two scenarios:

  • Twenty years hence (in the future), Ron's age will be x+20 x + 20 .
  • Thirty-six years ago (in the past), Ron's age was x36 x - 36 .

This results in the equation: x+20=5(x36) x + 20 = 5(x - 36)

2. Relevant Concepts

We will use algebra to solve for x x . We will apply the distributive property and basic algebraic operations to isolate x x .

3. Analysis and Detail

Start by expanding the equation:

  1. Distribute the 5: x+20=5x180 x + 20 = 5x - 180

  2. Rearrange to isolate x x : 20+180=5xx200=4x 20 + 180 = 5x - x \\ 200 = 4x

  3. Divide each side by 4: x=2004=50 x = \frac{200}{4} = 50

4. Verify and Summarize

To verify, let's check Ron's age:

  • Present age: 50 50
  • Age in 20 years: 50+20=70 50 + 20 = 70
  • Age 36 years ago: 5036=14 50 - 36 = 14
  • Five times the age 36 years ago: 5×14=70 5 \times 14 = 70

Both calculations confirm that both expressions for his age match.

Final Answer

Ron’s present age is 50 \boxed{50} years.

This problem has been solved

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