# What is the maximum possible number of edges in a directed graph with no self loops having 8 vertices?

## Question

## Solution 1

The maximum number of edges in a directed graph with n vertices and no self-loops can be calculated using the formula n*(n-1).

Here's the step-by-step calculation:

- Identify the number of vertices. In this case, it's 8.
- Subtract 1 from the number of vertices. So, 8 - 1 = 7.
- Multiply the o Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

```
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI
```

## Similar Questions

What is the maximum number of edges in a bipartite graph having 10 vertices?Select one:a.24b.21c.25d.16

The column sum in an incidence matrix for a directed graph having no self loop is __________?Group of answer choices012equal to the number of edges

What is the maximum number of edges in a simple graph with n vertices. Justify your answer.

What is the maximum number of edges in a complete undirected graph with n vertices?nn(n−1)/2n^2 2n

A connected planar graph having 6 vertices, 7 edges contains _____________ regions.Select one:a.15b.3c.1d.11

## Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.