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Let g(x + y) = g(x) + g(y) and g(xy) = g(x)g(y). If g(x) is one-to-one and onto, what is g(0)?

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Let g(x + y) = g(x) + g(y) and g(xy) = g(x)g(y). If g(x) is one-to-one and onto, what is g(0)?
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Solution 1

The problem doesn't specify a language, but I'll continue in English.

To find g(0), we can use the properties of the function g given in the problem.

First, let's use the property g(x + y) = g(x) + g(y). If we set x = y = 0, we get:

g(0 + 0) = g(0) + g(0) g(0) = 2g(0)

This implies that g(0) = 0, Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI  is a powerful AI-powered study tool designed to help you to solve study problem.
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