Let g(x + y) = g(x) + g(y) and g(xy) = g(x)g(y). If g(x) is one-to-one and onto, what is g(0)?
Question
Let g(x + y) = g(x) + g(y) and g(xy) = g(x)g(y). If g(x) is one-to-one and onto, what is g(0)?
Solution
The problem doesn't specify a language, but I'll continue in English.
To find g(0), we can use the properties of the function g given in the problem.
First, let's use the property g(x + y) = g(x) + g(y). If we set x = y = 0, we get:
g(0 + 0) = g(0) + g(0) g(0) = 2g(0)
This implies that g(0) = 0, because if g(0) were any other number, we would have a contradiction (since any number other than zero is not equal to twice itself).
So, g(0) = 0.
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