The function g(x) is increasing by a factor of 1.15 over every unit interval in x. This suggests that the function is exponential, because exponential functions increase by a constant factor over equal intervals.

The general form of an exponential function is g(x) = ab^x, where a is the initial value and b is the growth factor.

Given that g(0) = 1, we can substitute these values into the equation to find a.

1 = a*b^0
Since any number to the power of 0 is 1, a = 1.

The growth factor b is given as 1.15.

So, the function rule for g(x) could be g(x) = 1*1.15^x, or simplified to g(x) = 1.15^x.

Question

The function g(x) is increasing by a factor of 1.15 over every unit interval in x. This suggests that the function is exponential, because exponential functions increase by a constant factor over equal intervals.

The general form of an exponential function is g(x) = ab^x, where a is the initial value and b is the growth factor.

Given that g(0) = 1, we can substitute these values into the equation to find a.

1 = a*b^0
Since any number to the power of 0 is 1, a = 1.

The growth factor b is given as 1.15.

So, the function rule for g(x) could be g(x) = 1*1.15^x, or simplified to g(x) = 1.15^x.

Knowee AI · Accepted Answer

The function g(x) is increasing by a factor of 1.15 over every unit interval in x. This suggests that the function is exponential, because exponential functions increase by a constant factor over equal intervals.

The general form of an exponential function is g(x) = ab^x, where a is the initial value and b is the growth factor.

Given that g(0) = 1, we can substitute these values into the equation to find a.

1 = a*b^0
Since any number to the power of 0 is 1, a = 1.

The growth factor b is given as 1.15.

So, the function rule for g(x) could be g(x) = 1*1.15^x, or simplified to g(x) = 1.15^x.

A function g(x) increases by a factor of 1.15 over every unit interval in x and g(0)=1.Which could be a function rule for g(x)?

Question

A function g(x) increases by a factor of 1.15 over every unit interval in x and g(0)=1.

Solution

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