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In the electrolysis of water, if the mass of the gas collected at the anode isma and the mass of the gas collected at the cathode is mc, the value of(mc/ma) is

Question

In the electrolysis of water, if the mass of the gas collected at the anode is ma and the mass of the gas collected at the cathode is mc, the value of mcma \frac{m_c}{m_a} is

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Solution

To find the value of (mc/ma) in the electrolysis of water, we need to understand the process and the relationship between the masses of the gases collected at the anode and cathode.

  1. In the electrolysis of water, water molecules (H2O) are broken down into hydrogen gas (H2) and oxygen gas (O2).
  2. At the anode (positive electrode), oxygen gas is produced through the oxidation of hydroxide ions (OH-) from water. The equation for this reaction is: 4OH- -> 2H2O + O2 + 4e-.
  3. At the cathode (negative electrode), hydrogen gas is produced through the reduction of water molecules. The equation for this reaction is: 2H2O + 2e- -> 2OH- + H2.
  4. The mass of the gas collected at the anode is represented by ma, and the mass of the gas collected at the cathode is represented by mc.

Now, let's calculate the value of (mc/ma):

Since the equation for the reaction at the anode involves the production of oxygen gas, we can assume that ma represents the mass of oxygen gas collected.

Similarly, since the equation for the reaction at the cathode involves the production of hydrogen gas, we can assume that mc represents the mass of hydrogen gas collected.

Therefore, (mc/ma) represents the ratio of the mass of hydrogen gas collected to the mass of oxygen gas collected.

To calculate this ratio, we need to know the molar masses of hydrogen gas (H2) and oxygen gas (O2). The molar mass of hydrogen gas is 2 g/mol, and the molar mass of oxygen gas is 32 g/mol.

Using the molar masses, we can convert the masses of the gases collected into moles:

moles of oxygen gas (O2) = ma / 32 moles of hydrogen gas (H2) = mc / 2

Finally, we can calculate the value of (mc/ma) by dividing the moles of hydrogen gas by the moles of oxygen gas:

(mc/ma) = (mc / 2) / (ma / 32)

Simplifying this expression will give us the final value of (mc/ma).

Note: It is important to ensure that the masses of the gases collected are measured accurately and that the electrolysis process is carried out under controlled conditions to obtain reliable results.

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