On a hot stove burner, the temperature of a 500 g aluminum pan increases 120˚C. How much heat was added?
Question
On a hot stove burner, the temperature of a 500 g aluminum pan increases 120˚C. How much heat was added?
Solution
To solve this problem, we need to use the formula for heat transfer which is:
q = mcΔT
where:
- q is the heat added,
- m is the mass of the substance,
- c is the specific heat capacity of the substance, and
- ΔT is the change in temperature.
For aluminum, the specific heat capacity (c) is 0.897 J/g°C.
Now we can substitute the given values into the formula:
q = (500 g) * (0.897 J/g°C) * (120°C)
After performing the multiplication, we find that q = 53820 Joules.
So, the heat added to the aluminum pan is 53820 Joules.
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