if we toss this coin 88   times, then the probability of getting 66   or more heads  (to two decimal places) is .

Question

if we toss this coin 88   times, then the probability of getting 66   or more heads  (to two decimal places) is .
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Solution 1

To calculate the probability of getting 66 or more heads when tossing a coin 88 times, we need to use the binomial probability formula:

P(X=k) = C(n, k) * (p^k) * ((1-p)^(n-k))

where:

  • P(X=k) is the probability of k successes in n trials
  • C(n, k) is the combination of n items taken k at a time
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