he straight line L 1 has equation y = 3x – 4The straight line L 2 is perpendicular to L 1 and passes through the point (9, 5)Find an equation of line L 2

Step 1: Find the slope of line L1. The slope of line L1 is the coefficient of x, which is 3.

Step 2: Find the slope of line L2. Since L2 is perpendicular to L1, its slope is the negative reciprocal of the slope of L1. So, the slope of L2 is -1/3.

Step 3: Use the point-slope form of a line to find the equation of L2. The point-slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. We know that L2 passes through the point (9, 5), so x1 = 9 and y1 = 5.

Step 4: Substitute the values into the point-slope form: y - 5 = -1/3(x - 9).

Step 5: Simplify the equation to get it into slope-intercept form (y = mx + b). Distribute -1/3 on the right side to get y - 5 = -1/3x + 3.

Step 6: Add 5 to both sides to solve for y: y = -1/3x + 8.

So, the equation of line L2 is y = -1/3x + 8.