Compute the heat generated while transferring 96000 coulomb of charge in two hours through a potentialdifference of 40V
Question
Compute the heat generated while transferring 96000 coulomb of charge in two hours through a potential difference of 40V
Solution
Sure, to calculate the heat generated, we first need to find the work done, which is given by the formula:
Work Done (W) = Charge (Q) * Potential Difference (V)
Given: Charge (Q) = 96000 Coulombs Potential Difference (V) = 40 Volts
Substituting the given values into the formula, we get:
Work Done = 96000 Coulombs * 40 Volts = 3840000 Joules
Now, the heat generated is equal to the work done when there are no other forms of energy involved. Therefore, the heat generated is 3840000 Joules.
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