The LCM and HCF of two numbers are 240 and 12 respectively. If one of the numbers is 60, then find the other number.
Question
The LCM and HCF of two numbers are 240 and 12 respectively. If one of the numbers is 60, then find the other number.
Solution
Sure, here is the step by step solution:
Step 1: We know that the product of two numbers is equal to the product of their LCM and HCF.
So, let's denote the two numbers as a and b, their LCM as L and their HCF as H. We have:
a * b = L * H
Step 2: We know that one of the numbers (a) is 60, the LCM (L) is 240 and the HCF (H) is 12. Substituting these values into the equation we get:
60 * b = 240 * 12
Step 3: Now, we can solve for b:
b = (240 * 12) / 60
Step 4: Calculate the value:
b = 2880 / 60
b = 48
So, the other number is 48.
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