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If an unsigned integer contain 2 bytes then what will be the range of numbers?Options :-32768 to +327670 to 65535-128 to +128none of the above

Question

If an unsigned integer contain 2 bytes then what will be the range of numbers?

Options :

  • 32768 to +32767
  • 0 to 65535
  • -128 to +128
  • none of the above
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Solution

Break Down the Problem

  1. Identify the size of the unsigned integer.
  2. Calculate the range of an unsigned integer using the formula.

Relevant Concepts

  • An unsigned integer does not include negative values.
  • The range of an unsigned integer can be calculated with the formula:
    0 to (2n1) 0 \text{ to } (2^n - 1) where n n is the number of bits.

Analysis and Detail

  1. Determine the number of bits for the 2 bytes:

    • Since 1 byte = 8 bits, then 2 bytes = 2×8=16 2 \times 8 = 16 bits.
  2. Calculate the maximum value:

    • Using the formula for unsigned integers:
      0 to (2161) 0 \text{ to } (2^{16} - 1)
    • Calculating 216 2^{16} :
      216=65536 2^{16} = 65536
    • So the maximum value is:
      655361=65535 65536 - 1 = 65535

Verify and Summarize

  • The range of an unsigned integer that contains 2 bytes is from 0 to 65535. This means the total range is:
    • Lower Bound: 0
    • Upper Bound: 65535

Final Answer

The correct option is: 0 to 65535.

This problem has been solved

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