Knowee
Questions
Features
Study Tools

What are the largest 4-digit and the smallest 3-digit numbers divisible by 6, 15, 21 and 24?Options 9235, 420 9980, 840 9240, 840 9999, 999

Question

What are the largest 4-digit and the smallest 3-digit numbers divisible by 6, 15, 21 and 24?

Options:

  • 9235, 420
  • 9980, 840
  • 9240, 840
  • 9999, 999
🧐 Not the exact question you are looking for?Go ask a question

Solution

To find the largest 4-digit number divisible by 6, 15, 21, and 24, we need to find the least common multiple (LCM) of these numbers. The LCM of 6, 15, 21, and 24 is 840.

Now, to find the largest 4-digit number divisible by 840, we divide the largest 4-digit number, 9999, by 840. The quotient is 11 and the remainder is 879. So, we subtract 879 from 9999 to get the largest 4-digit number divisible by 840, which is 9120.

To find the smallest 3-digit number divisible by 840, we divide the smallest 3-digit number, 100, by 840. The quotient is 0 and the remainder is 100. So, we add 840 - 100 to get the smallest 3-digit number divisible by 840, which is 840.

So, the largest 4-digit number and the smallest 3-digit number divisible by 6, 15, 21, and 24 are 9120 and 840, respectively. However, none of the options provided match these numbers.

This problem has been solved

Similar Questions

The largest four digit number exactly divisible by each of 12, 15, 18 and 27 is:a.9720b.9930c.9960d.9690

What is the largest six-digit number that is divisible by 8, 12, 16, 24, and 32?

Find the largest number of four digits which is exactly divisible by 88 ?9955994499889966

Find the greatest five-digit number which is divisible by 7, 10, 15, 21 and 28.Choices:- 99540 99988 99960 99990Save AnswerSkip this questionFinish Exam

The greatest four digit number which is divisible by 18, 25, 30, and 48 is:Options :A] 9000B] 9200C] 7200D] 9729

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.