Sodium (Na) has an atomic number of 11. Its electron configuration (by shells) is therefore:A 2, 8, 1B 1, 2, 8C 2, 2, 7D 2, 7, 2*1 pointABCD
Question
Sodium (Na) has an atomic number of 11. Its electron configuration (by shells) is therefore:
- A 2, 8, 1
- B 1, 2, 8
- C 2, 2, 7
- D 2, 7, 2
1 point
A B C D
Solution
The correct answer is A. Sodium (Na) has an atomic number of 11. The electron configuration of an atom is determined by the number of electrons in the atom. The first shell can hold up to 2 electrons, the second shell can hold up to 8 electrons, and the third shell can hold up to 8 electrons. Therefore, Sodium with 11 electrons would have an electron configuration of 2 electrons in the first shell, 8 in the second, and 1 in the third. So, the electron configuration (by shells) of Sodium is 2, 8, 1.
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