The gravitational acceleration on the surface of the earth of radius R and mean density ρ is43GπR2ρ43Gπ2R2ρ23GπRρ43GπRρ

It seems like there's a mistake in your question as it's not clear. However, I can tell you how to calculate the gravitational acceleration on the surface of the earth.

The gravitational acceleration on the surface of the earth can be calculated using the formula:

g = GM/R^2

where:

• G is the gravitational constant, approximately equal to 6.674 x 10^-11 N(m/kg)^2,
• M is the mass of the earth, and
• R is the radius of the earth.

If you want to express the mass of the earth in terms of its density, you can use the formula for the volume of a sphere, which is V = 4/3πR^3. The mass is then density times volume, or M = ρV = ρ * 4/3πR^3.

Substituting this into the original formula gives:

g = G * ρ * 4/3πR^3 / R^2 = 4/3 * G * ρ * π * R

This is the formula for the gravitational acceleration on the surface of the earth in terms of the radius of the earth and its mean density.