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There exists only one possible 3NF decomposition for any relation schema and any set of functional dependencies.Question 4Select one:TrueFalse

Question

There exists only one possible 3NF decomposition for any relation schema and any set of functional dependencies.

Question 4

Select one:

  • True
  • False
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Solution

The statement "There exists only one possible 3NF decomposition for any relation schema and any set of functional dependencies" is False.

Explanation:

  1. Understanding 3NF (Third Normal Form): 3NF is a type of database normalization that aims to eliminate transitive dependencies and ensure that every non-prime attribute is non-transitively dependent on every key of the table.

  2. Decompositions: A decomposition of a relation into 3NF involves splitting the relation into two or more relations in such a way that the overall structure maintains all the original functional dependencies and minimizes redundancy.

  3. Uniqueness of Decompositions: While a relation can be decomposed into 3NF, there can be multiple ways to achieve this. The choice of which attributes to split off into different relations can vary based on interpretation of the functional dependencies, leading to different valid 3NF decompositions.

  4. Example: Consider a relation R(A, B, C) with functional dependencies {A → B, A → C}. One could decompose it into R1(A, B) and R2(A, C), or alternatively, one might choose different combinations based on other dependencies or design considerations.

Conclusion:

Given that multiple valid decompositions can exist, the statement is indeed False. There is not a unique decomposition into 3NF for any given relation schema and set of functional dependencies.

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