A container holds 60.0 mL of nitrogen at 30.0 degrees Celsius. What will be its volume if the temperature increases to 65.0 degrees Celsius?
Question
A container holds 60.0 mL of nitrogen at 30.0 degrees Celsius. What will be its volume if the temperature increases to 65.0 degrees Celsius?
Solution
This problem can be solved using Charles's Law, which states that the volume of a gas is directly proportional to its temperature in Kelvin, as long as the pressure and the amount of gas are kept constant. The formula for Charles's Law is V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume, and T2 is the final temperature.
Here are the steps to solve the problem:
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Convert the initial and final temperatures from Celsius to Kelvin. The formula to convert Celsius to Kelvin is K = °C + 273.15. So, T1 = 30.0°C + 273.15 = 303.15 K and T2 = 65.0°C + 273.15 = 338.15 K.
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Substitute the known values into Charles's Law formula. So, (60.0 mL / 303.15 K) = V2 / 338.15 K.
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Solve for V2 by multiplying both sides of the equation by 338.15 K. So, V2 = (60.0 mL / 303.15 K) * 338.15 K.
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Calculate V2 to find the final volume. V2 ≈ 67.0 mL.
So, if the temperature of the nitrogen increases from 30.0 degrees Celsius to 65.0 degrees Celsius, the volume of the nitrogen will increase to approximately 67.0 mL.
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