The line is perpendicular to y = 16 x + 5 and passes through the point (1, 6).

The first step is to find the slope of the given line. The equation of the line is in the form y = mx + c, where m is the slope. So, the slope of the given line y = 16x + 5 is 16.

The slope of a line perpendicular to a given line is the negative reciprocal of the slope of the given line. Therefore, the slope of the line perpendicular to y = 16x + 5 is -1/16.

The equation of a line is given by y = mx + c. We know the slope (m) is -1/16 and the line passes through the point (1, 6). We can substitute these values into the equation to find the y-intercept (c).

6 = (-1/16)*1 + c 6 = -1/16 + c c = 6 + 1/16 c = 97/16

Therefore, the equation of the line that is perpendicular to y = 16x + 5 and passes through the point (1, 6) is y = -1/16x + 97/16.