The time period of oscillation for a spring-mass system is given by the formula T = 2π√(m/k).

However, in this case, we have two springs attached to the block. When two springs are attached in parallel like this, their spring constants add up. So, the effective spring constant (k_eff) for this system is 2k.

Substituting this into the formula, we get T = 2π√(m/2k).

So, the time period of oscillation for this system is T = 2π√(m/2k).

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The time period of oscillation for a spring-mass system is given by the formula T = 2π√(m/k).

However, in this case, we have two springs attached to the block. When two springs are attached in parallel like this, their spring constants add up. So, the effective spring constant (k_eff) for this system is 2k.

Substituting this into the formula, we get T = 2π√(m/2k).

So, the time period of oscillation for this system is T = 2π√(m/2k).

Knowee AI · Accepted Answer

The time period of oscillation for a spring-mass system is given by the formula T = 2π√(m/k).

However, in this case, we have two springs attached to the block. When two springs are attached in parallel like this, their spring constants add up. So, the effective spring constant (k_eff) for this system is 2k.

Substituting this into the formula, we get T = 2π√(m/2k).

So, the time period of oscillation for this system is T = 2π√(m/2k).

Two identical springs of spring constant k are attached to a block ofmass m and to fixed supports as shown in the figure. The time period ofoscillation is

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