What is the best estimate of the number of atoms in a piece of metal of volume 50 cm3?A 5  10 15 B 5  10 25 C 5  10 29 D 5  10 31

To estimate the number of atoms in a piece of metal, we need to know the density of the metal and the atomic mass of the metal. However, without this information, we can make a rough estimate using the density of a common metal like iron and the atomic mass of iron.

1. First, we need to convert the volume from cm3 to m3 because the density of metals is usually given in kg/m3. There are 1,000,000 cm3 in a m3, so 50 cm3 is 50/1,000,000 = 0.00005 m3.

2. The density of iron is approximately 7,874 kg/m3. So, the mass of the iron piece would be volume x density = 0.00005 m3 x 7,874 kg/m3 = 0.394 kg.

3. The atomic mass of iron is approximately 56 atomic mass units (u), and 1 u is approximately 1.66 x 10^-27 kg. So, the mass of one iron atom is 56 u x 1.66 x 10^-27 kg/u = 9.296 x 10^-26 kg.

4. Finally, we can estimate the number of atoms by dividing the total mass of the iron piece by the mass of one atom: 0.394 kg / 9.296 x 10^-26 kg = 4.24 x 10^28 atoms.

So, the best estimate from the given options would be C: 5 x 10^29.