Find the second derivative of the function*y''= x^4 -2(x^3 ) + x^2y' = 24x - 12y''= 12x^2 -12x + 2y''= 4x^3 - 6x^2 + 2x
Question
Find the second derivative of the function
( y'' = x^4 - 2(x^3) + x^2y' = 24x - 12y'' = 12x^2 - 12x + 2y'' = 4x^3 - 6x^2 + 2x \
Solution
To find the second derivative of the function, we need to differentiate it twice with respect to x.
Given the function y'' = 4x^3 - 6x^2 + 2x, we can differentiate it once to find the first derivative:
y' = d/dx (4x^3 - 6x^2 + 2x) = 12x^2 - 12x + 2
Now, we can differentiate the first derivative again to find the second derivative:
y'' = d/dx (12x^2 - 12x + 2) = 24x - 12
Therefore, the second derivative of the function y'' = 4x^3 - 6x^2 + 2x is y'' = 24x - 12.
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