Knowee
Questions
Features
Study Tools

Find the magnitude of the tension in each supporting cable shown below. In each case, the weight of the suspended body

Question

Find the magnitude of the tension in each supporting cable shown below.

In each case, the weight of the suspended body

🧐 Not the exact question you are looking for?Go ask a question

Solution

To solve the problem of finding the magnitude of the tension in each supporting cable, we will proceed with the following steps:

1. Breakdown the Problem

  1. Identify the weights and angles involved with the cables.
  2. Set up the equilibrium equations for the system.

2. Relevant Concepts

  1. For a suspended body in static equilibrium, the sum of the vertical forces must equal zero, as must the sum of the horizontal forces. This can be expressed as:

    • ΣFx=0\Sigma F_x = 0
    • ΣFy=0\Sigma F_y = 0
  2. Use trigonometric identities to resolve tensions into their components:

    • Ticos(θi)T_i \cos(\theta_i) for horizontal components
    • Tisin(θi)T_i \sin(\theta_i) for vertical components

3. Analysis and Detail

  1. Let T1 T_1 and T2 T_2 be the tensions in the cables at angles θ1 \theta_1 and θ2 \theta_2 respectively.

  2. We can express the equations based on equilibrium:

    • Vertical forces: T1sin(θ1)+T2sin(θ2)=W T_1 \sin(\theta_1) + T_2 \sin(\theta_2) = W
    • Horizontal forces: T1cos(θ1)=T2cos(θ2) T_1 \cos(\theta_1) = T_2 \cos(\theta_2)
  3. Rearranging the horizontal forces equation gives: T2=T1cos(θ1)cos(θ2) T_2 = T_1 \frac{\cos(\theta_1)}{\cos(\theta_2)}

  4. Substitute T2 T_2 into the vertical forces equation: T1sin(θ1)+(T1cos(θ1)cos(θ2))sin(θ2)=W T_1 \sin(\theta_1) + \left( T_1 \frac{\cos(\theta_1)}{\cos(\theta_2)} \right) \sin(\theta_2) = W

4. Verify and Summarize

  1. Rearrange to isolate T1 T_1 : T1(sin(θ1)+cos(θ1)cos(θ2)sin(θ2))=W T_1 \left( \sin(\theta_1) + \frac{\cos(\theta_1)}{\cos(\theta_2)} \sin(\theta_2) \right) = W Hence, T1=Wsin(θ1)+cos(θ1)cos(θ2)sin(θ2) T_1 = \frac{W}{\sin(\theta_1) + \frac{\cos(\theta_1)}{\cos(\theta_2)} \sin(\theta_2)}

  2. Substitute T1 T_1 back into the equation for T2 T_2 : T2=T1cos(θ1)cos(θ2) T_2 = T_1 \frac{\cos(\theta_1)}{\cos(\theta_2)}

Final Answer

The magnitudes of the tensions in the cables can be expressed as:

  • T1=Wsin(θ1)+cos(θ1)cos(θ2)sin(θ2) T_1 = \frac{W}{\sin(\theta_1) + \frac{\cos(\theta_1)}{\cos(\theta_2)} \sin(\theta_2)}
  • T2=Wcos(θ1)cos(θ2)(sin(θ1)+cos(θ1)cos(θ2)sin(θ2)) T_2 = \frac{W \cos(\theta_1)}{\cos(\theta_2) \left( \sin(\theta_1) + \frac{\cos(\theta_1)}{\cos(\theta_2)} \sin(\theta_2) \right)}

Make sure to substitute the appropriate values for W W , θ1 \theta_1 , and θ2 \theta_2 to find the numerical values of T1 T_1 and T2 T_2 .

This problem has been solved

Similar Questions

Une masse de 10 kg est suspendue à deux câbles de même longueur. Si l’angle entre les câbles est de 45°, quelle est la force de tension dans chacun des câbles?

The mass of a lift is 500 kg. When it ascends with an acceleration of 2 m/s2, the tension in the cable will be [g = 10 m/s2]A 6000 N B 5000 N C 4000 N D 50 N

An object of mass m is hanging by a string from the roof of an elevator. The elevator is moving downward and slowing down. What is the tension in the string?

Material Testing: A steel wire with a cross sectional area of 0.2 m2 is subjected to a tension loading force of 50N, calculate the stress applied to this wire.

Calculate the magnitude of the component of the brick’s weight which acts parallel to the slope.

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.