Which of the following exactly divides x, where x is the sum of the first 15 prime numbers?

To find out which of the following numbers exactly divides x, where x is the sum of the first 15 prime numbers, we need to first calculate the value of x.

The first step is to identify the first 15 prime numbers. The prime numbers are numbers that are only divisible by 1 and themselves. Starting from 2, we can list the first 15 prime numbers as follows:

2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47

Next, we need to sum up these prime numbers to find the value of x. Adding them up, we get:

2 + 3 + 5 + 7 + 11 + 13 + 17 + 19 + 23 + 29 + 31 + 37 + 41 + 43 + 47 = 460

So, x is equal to 460.

Now, we need to determine which of the given numbers exactly divides 460. Without knowing the specific numbers provided, we can check each of them by dividing 460 by each number and checking if the remainder is zero.

By performing the division, if the remainder is zero, then that number exactly divides 460. If the remainder is not zero, then that number does not divide 460.

By following these steps, we can determine which of the given numbers exactly divides x, where x is the sum of the first 15 prime numbers.