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A quadrant has a radius of 45 m. Find the perimeter of the quadrant. Take π as 3.14.

Question

A quadrant has a radius of 45 m. Find the perimeter of the quadrant. Take π as 3.14.

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Solution

To find the perimeter of a quadrant, we need to add the length of the arc (which is a quarter of the circumference of the full circle) and twice the radius (which are the two straight sides of the quadrant).

Step 1: Find the circumference of the full circle. The formula for the circumference of a circle is 2πr. Here, r is the radius, which is given as 45 m. So, the circumference is 2 * 3.14 * 45 = 282.6 m.

Step 2: Since a quadrant is a quarter of a circle, the length of the arc of the quadrant is a quarter of the full circumference. So, the length of the arc is 282.6 / 4 = 70.65 m.

Step 3: The perimeter of the quadrant is the sum of the length of the arc and twice the radius. So, the perimeter is 70.65 + 2 * 45 = 160.65 m.

So, the perimeter of the quadrant is 160.65 m.

This problem has been solved

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